Shell and Tube Heat Exchanger, Pressure Vessel,Types, Working,Uses,Manufacturing,Functions,Drawings

Detailed steps to determine the necessary length of the  parallel flow  heat exchanger.  In this tutorial, we'll explore how to size a parallel flow concentric heat exchanger.   Here, hot oil is cooled by water that jackets it. The given information includes: Oil: Enters at 100°C and leaves at 60°C Mass flow rate: 0.15 kg/s (kilograms per second) Heat capacity: 2131 J/kg°C (joules per kilogram degrees Celsius) Convective heat transfer coefficient: 38.8 W/m²°C (watts per meter squared degrees C) Water: Enters at 25°C and leaves at 50°C Convective heat transfer coefficient: 2250 W/m²°C (watts per meter squared degrees C)   We aim to determine the length of the tube required for the necessary cooling. We'll make a couple of assumptions: negligible heat loss to the surroundings and a thin wall between the fluids, implying no conductive heat resistance between them.   Governing Equation Our heat transfer rate (𝑄) is given by the equation: Q=U×A×ΔT log mean ​ ...

  Steam Requirements for Heating Water in a Heat Exchanger When designing and operating heat exchangers, one common question is: how much steam is required to raise the temperature of water to a desired level? This blog provides a detailed step-by-step guide to perform these calculations using two different examples. Example 1: Case Study:   We have a hot water absorption heater with the following parameters:   Mass flow rate of hot water: 131.9 cubic meters per hour (36.63 liters per second). Initial temperature of water: 85°C. Desired temperature increase: From 85°C to 92°C (ΔT = 7°C). The specific enthalpy of steam at 8 bar is 2767 kJ/kg, and the specific heat capacity of water is 4.19 kJ/kg°C.   Solution:   Calculate the Heat Load (Q): 𝑄=𝑚˙×𝐶𝑝×Δ𝑇 𝑚˙=36.63 kg/s C p =4.19 kJ/kg°C Δ𝑇=7°𝐶 Q=36.63×4.19×7=1074 kJ/s   Calculate the Required Steam Flow Rate: Δℎ=2767−419=2348 kJ/kg 𝑚˙steam=𝑄/Δℎ=1074/2348=0.457 kg/s ...